x/x-2+x/x^2-4=x+3/x+2

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Solution for x/x-2+x/x^2-4=x+3/x+2 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x/(x^2)+x/x-4-2 = x+3/x+2 // - x+3/x+2

x/(x^2)-x-(3/x)+x/x-4-2-2 = 0

x/(x^2)-x-3*x^-1+x/x-4-2-2 = 0

-1*x^1-2*x^-1-7*x^0 = 0

(-1*x^2-7*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-7*x^1-2*x^0) = 0

x^1

-x^2-7*x-2 = 0

-x^2-7*x-2 = 0

DELTA = (-7)^2-(-2*(-1)*4)

DELTA = 41

DELTA > 0

x = (41^(1/2)+7)/(-1*2) or x = (7-41^(1/2))/(-1*2)

x = (41^(1/2)+7)/(-2) or x = (7-41^(1/2))/(-2)

x in { (41^(1/2)+7)/(-2), (7-41^(1/2))/(-2)} 

x in { (41^(1/2)+7)/(-2), (7-41^(1/2))/(-2) }

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